Published by:
CGP EDU Academic Team
Published on: September 13, 2026
The average energy released per fission for the nucleus of 
is 190 MeV . When all the atoms of 47 g pure 
undergo fission process, the energy released is 
. The value of 
is 
.(Avogadro Number 
per mole)
Text Solution
Verified by ExpertsThe correct answer is:
228
(228)
The number of 
atoms in 47 g is determined using Avogadro's number.
Molar mass of 
is 
, so the number of moles is 
.
The total number of atoms is 
.
Since each fission releases 190 MeV , the total energy released is:
.
Calculating the numerator: 
.
Therefore: 
, giving 
.
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